Math116

ProblemsAnswerGrade
Problem-1
ax+y=56
/3
bx+y=56
x+3x=56
56/4= 14
x=14
56-14=42
y=42
check 14+42=56 or 14+(14*3)=56/3
cbefore we use elimination, we simplify the irregular equating by dividing by 25,000:
sweet equation for b): 7x + 8y = 288
in order to hap a variable, multiply the first equation by -7:
new equation for a): -7x + -7y = -266
Elimination: add the dickens equations and the xs cancel step to the fore:
y = 22
x = 38-22 = 16/3
d For the first equation, the intercepts are (56, 0) and (0,56). The intercept for the second equation is (0, 0).



The lines would queer at (14, 42)/3

Problem-2
ax+y=38
/3
b$175,000x+$200,000y=$7,200,000
/3
cBefore we use elimination, we simplify the second equation by dividing by 25,000:
new equation for b): 7x + 8y = 288
in order to eliminate a variable, multiply the first equation by -7:
new equation for a): -7x + -7y = -266
Elimination: add the two equations and the xs cancel out:
y = 22
x = 38-22 = 16
There are 16 homes with push down proposal #1, and
there are 22 homes with floor plan #2.
/3

Problem-3
aAn $80. Fee in addition to an hourly allowance is more expensive than an hourly charge with no extra fees. Quick run away is the better deal.
/3
bQuick Move offers the better deal for less than 4 hours when h < 4. When h = 4, both companies have the same deal and neither one and only(a) is better./3
cHeavy lifting 35x +80 = h Quick social movement 55x = h /3

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